What is the derivative of 1/(\sqrt[4]{x}) ?

The derivative of 1/(\sqrt[4]{x}) is -1/(4x^{5/4)}

What is the first derivative of 1/(\sqrt[4]{x}) ?

The first derivative of 1/(\sqrt[4]{x}) is -1/(4x^{5/4)}

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- \frac{1}{4 x ^{\frac{5}{4}}}

Solution steps

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- \frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{4} x^{- \frac{1}{4} - 1}

Simplify

- \frac{1}{4} x^{- \frac{1}{4} - 1} : - \frac{1}{4 x ^{\frac{5}{4}}}

= - \frac{1}{4 x ^{\frac{5}{4}}}

n = 0 \sum \infty (x + 1)^{n}

\frac{d}{d x} (2 x y^{4} - 3)

\frac{\partial}{\partial x} (2 x^{3} y + sin (x^{3}))

y^{^{'}} + 4 y = sin (3 t)

\int (2 x^{2} + 3 x)^{3} d x

What is the derivative of 1/(\sqrt[4]{x}) ?
The derivative of 1/(\sqrt[4]{x}) is -1/(4x^{5/4)}
What is the first derivative of 1/(\sqrt[4]{x}) ?
The first derivative of 1/(\sqrt[4]{x}) is -1/(4x^{5/4)}