What is the tangent of f(x)=x^2-9,(-2,-5) ?

The tangent of f(x)=x^2-9,(-2,-5) is y=-4x-13

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tangent of f(x)=x^2-9,(-2,-5)

tangent of

f (x) = x^{2} - 9, (- 2, - 5)

y = - 4 x - 13

Solution steps

Find the slope of

f (x) = x^{2} - 9 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 9

(- 2, - 5) : m = - 4

Find the line with slope m=

- 4

and passing through

(- 2, - 5) : y = - 4 x - 13

y = - 4 x - 13

\int \frac{x ^{3}}{x ^{4} + 5} d x

\frac{d}{d x} (\frac{1}{x ( 8 + ln ( x ) )})

x \to - 3 lim (\frac{x + 2}{x + 3})

x \to - 3 lim (\frac{x - 2}{x + 5})

\frac{d}{d x} (x^{\frac{1}{2}} y^{\frac{1}{2}})

What is the tangent of f(x)=x^2-9,(-2,-5) ?
The tangent of f(x)=x^2-9,(-2,-5) is y=-4x-13