What is the first derivative of 3x-7 ?

The first derivative of 3x-7 is 3

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derivative of 3x-7

\frac{d}{d x} (3 x - 7)

3

Solution steps

\frac{d}{d x} (3 x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (7)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (7) = 0

= 3 - 0

Simplify

= 3

\int \frac{1}{x e ^{- x}} d x

\frac{d}{d x} ((5 x^{3} + 3) (x^{4} - 2 x))

t e^{2 t} sin (t)

\frac{d y}{d x} + 2 y = e^{- x}