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Popular >

area y=5,y=x^2+1

Solution

area

y = 5, y = x^{2} + 1

Solution

\frac{32}{3}

+1

Decimal Notation

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} 5 - (x^{2} + 1) d x

Solve

\int_{- 2}^{2} 5 - (x^{2} + 1) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Popular Examples

simplify (x-2)^2sqrt(-3x)simplify

(x - 2)^{2} - 3 x

integral from-2 to 0 of \sqrt[3]{x^2}

derivative of x^2sqrt(3-x)

\frac{d}{d x} (x^{2} 3 - x)

integral of 1/(5+x^2)

\int \frac{1}{5 + x ^{2}} d x

integral of (ln(y))/(log_{10)(y)}

\int \frac{ln ( y )}{lo g _{10} ( y )} d y

Frequently Asked Questions (FAQ)

What is area y=5,y=x^2+1 ?
The answer to area y=5,y=x^2+1 is 32/3