What is the sum from n=1 to infinity of (2n)/(5n-3) ?

The sum from n=1 to infinity of (2n)/(5n-3) is diverges

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sum from n=1 to infinity of (2n)/(5n-3)

n = 1 \sum \infty \frac{2 n}{5 n - 3}

diverges

Solution steps

n = 1 \sum \infty \frac{2 n}{5 n - 3}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{n}{5 n - 3}

Apply Series Divergence Test:

diverges

= 2 diverges

= diverges

e^{s i n (2 x)}

\int_{0}^{1} 2 (1 - x) d x

\int \frac{4 x}{4 x ^{2} + 1} d x

\frac{d}{d x} (\frac{2 x}{( x ^{2} - 3 ) ^{2}})

y = e^{- x} cos (2 x)

What is the sum from n=1 to infinity of (2n)/(5n-3) ?
The sum from n=1 to infinity of (2n)/(5n-3) is diverges