What is the sum from n=1 to infinity of (2n+1)^{-6} ?

The sum from n=1 to infinity of (2n+1)^{-6} is converges

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sum from n=1 to infinity of (2n+1)^{-6}

n = 1 \sum \infty (2 n + 1)^{- 6}

converges

Solution steps

n = 1 \sum \infty (2 n + 1)^{- 6}

Apply Series Integral Test:

converges

= converges

9 cos (\frac{2}{5} x)

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\frac{d}{d x} (- x^{2} + \frac{x}{3} - 3)

\int - 5 x e^{x^{2}} d x

What is the sum from n=1 to infinity of (2n+1)^{-6} ?
The sum from n=1 to infinity of (2n+1)^{-6} is converges