What is the solution for (dy)/(dx)-sin(x+y)=0 ?

The solution for (dy)/(dx)-sin(x+y)=0 is y=2arctan((-2-x-c_{1})/(x+c_{1)})+2pin-x

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(dy)/(dx)-sin(x+y)=0

\frac{d y}{d x} - sin (x + y) = 0

y = 2 arctan (\frac{- 2 - x - c _{1}}{x + c _{1}}) + 2 πn - x

Solution steps

\frac{d y}{d x} - sin (x + y) = 0

Solve using substitution:

y = 2 arctan (\frac{- 2 - x - c _{1}}{x + c _{1}}) + 2 πn - x

y = 2 arctan (\frac{- 2 - x - c _{1}}{x + c _{1}}) + 2 πn - x

\frac{d x}{d y} = \frac{( y - x )}{y + x}

y = 2, y = x^{2} + 1

\frac{d}{d x} ((lo g_{2} (x))^{4})

\frac{d}{d x} (x^{2} - 7 x + 7)

y^{^{''}} + 3 y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = 1

What is the solution for (dy)/(dx)-sin(x+y)=0 ?
The solution for (dy)/(dx)-sin(x+y)=0 is y=2arctan((-2-x-c_{1})/(x+c_{1)})+2pin-x