What is area x^3-13x^2+40x,-x^3+13x^2-40x ?

The answer to area x^3-13x^2+40x,-x^3+13x^2-40x is 863/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x^3-13x^2+40x,-x^3+13x^2-40x

area

x^{3} - 13 x^{2} + 40 x, - x^{3} + 13 x^{2} - 40 x

\frac{863}{3}

Decimal Notation

287.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{8} x^{3} - 13 x^{2} + 40 x - (- x^{3} + 13 x^{2} - 40 x) d x

Solve

\int_{0}^{8} x^{3} - 13 x^{2} + 40 x - (- x^{3} + 13 x^{2} - 40 x) d x : \frac{863}{3}

The area is:

= \frac{863}{3}

\int 900 - 36 x^{2} d x

y^{^{'}} = 13 x y - 16 x

\int \frac{( 2 x ^{3} + x - 1 )}{x ^{3} + x ^{2} - 4 x - 4} d x

x \to 2 lim (π^{2} - 2 x + 5)

x (2 x + 7)^{\frac{2}{3}}

What is area x^3-13x^2+40x,-x^3+13x^2-40x ?
The answer to area x^3-13x^2+40x,-x^3+13x^2-40x is 863/3