What is (\partial)/(\partial x)(-2ycos(x)) ?

The answer to (\partial)/(\partial x)(-2ycos(x)) is 2ysin(x)

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(\partial)/(\partial x)(-2ycos(x))

\frac{\partial}{\partial x} (- 2 y cos (x))

2 y sin (x)

Solution steps

\frac{\partial}{\partial x} (- 2 y cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 y \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= - 2 y (- sin (x))

Simplify

= 2 y sin (x)

d er i v a t i v e tan (9 x)

\int e^{2 x} sin (2 x) d x

\frac{d}{d x} y + y x^{7} = 0

x \to 2 lim (- f (x))

\int_{0}^{2} x^{5} d x

What is (\partial)/(\partial x)(-2ycos(x)) ?
The answer to (\partial)/(\partial x)(-2ycos(x)) is 2ysin(x)