derivative of (x^2+1^{0.6})

Lösung

\frac{d}{d x} ((x^{2} + 1)^{0.6})

\frac{1.2 x}{( x ^{2} + 1 ) ^{0.4}}

Schritte zur Lösung

\frac{d}{d x} ((x^{2} + 1)^{0.6})

Wende die Kettenregel an:

\frac{0.6}{( x ^{2} + 1 ) ^{0.4}} \frac{d}{d x} (x^{2} + 1)

= \frac{0.6}{( x ^{2} + 1 ) ^{0.4}} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= \frac{0.6}{( x ^{2} + 1 ) ^{0.4}} \cdot 2 x

Vereinfache

\frac{0.6}{( x ^{2} + 1 ) ^{0.4}} \cdot 2 x : \frac{1.2 x}{( x ^{2} + 1 ) ^{0.4}}

= \frac{1.2 x}{( x ^{2} + 1 ) ^{0.4}}

\int \frac{ln ( x )}{x 1 + ( ln ( x ) ) ^{2}} d x

\frac{d}{d t} (- 8 cos (t))

\frac{d}{d x} (ln (\frac{x + a}{y}))

\int \frac{1}{x ^{2} - 2 x + 82} d x

\int \frac{sin ( 1 + x )}{x + 1} d x