What is the integral of sqrt(7x+1) ?

The integral of sqrt(7x+1) is 2/21 (7x+1)^{3/2}+C

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integral of sqrt(7x+1)

\int 7 x + 1 d x

\frac{2}{21} (7 x + 1)^{\frac{3}{2}} + C

Solution steps

\int 7 x + 1 d x

Apply u-substitution

: \int \frac{u}{7} d u

= \int \frac{u}{7} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{7} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 7 x + 1

= \frac{1}{7} \cdot \frac{2}{3} (7 x + 1)^{\frac{3}{2}}

Simplify

\frac{1}{7} \cdot \frac{2}{3} (7 x + 1)^{\frac{3}{2}} : \frac{2}{21} (7 x + 1)^{\frac{3}{2}}

= \frac{2}{21} (7 x + 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{21} (7 x + 1)^{\frac{3}{2}} + C

\frac{\partial}{\partial y} (tan (2 x + y))

0 = 2 x + 1 - 2 y y^{^{'}}

\int 2 [1 - cos^{2} (2 x)] d x

\int cos (x) (2 + sin (x))^{6} d x

What is the integral of sqrt(7x+1) ?
The integral of sqrt(7x+1) is 2/21 (7x+1)^{3/2}+C