What is implicit (dy)/(dx),y= 1/x ?

The answer to implicit (dy)/(dx),y= 1/x is (dy)/(dx)=-1/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

implicit (dy)/(dx),y= 1/x

implicit derivative

\frac{d y}{d x}, y = \frac{1}{x}

\frac{d y}{d x} = - \frac{1}{x ^{2}}

Solution steps

y = \frac{1}{x}

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = - \frac{1}{x ^{2}}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{1}{x ^{2}}

\frac{d y}{d x} = - \frac{1}{x ^{2}}

\int \frac{1}{( x - 1 )} d x

\frac{d}{d x} (arcsec (x))

y^{^{''}} + x^{2} y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = 2

d er i v a t i v e f (x) = \frac{x}{x + 5}

\int \frac{1}{8 x + 3} d x

What is implicit (dy)/(dx),y= 1/x ?
The answer to implicit (dy)/(dx),y= 1/x is (dy)/(dx)=-1/(x^2)