What is the limit as x approaches 0+of sin((5pi)/6 e^{sqrt(x)}) ?

The limit as x approaches 0+of sin((5pi)/6 e^{sqrt(x)}) is 1/2

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limit as x approaches 0+of sin((5pi)/6 e^{sqrt(x)})

x \to 0 + lim (sin (\frac{5 π}{6} e^{x}))

\frac{1}{2}

Decimal Notation

0.5

Solution steps

x \to 0 + lim (sin (\frac{5 π}{6} e^{x}))

Plug in the value

x = 0

= sin (\frac{5 π}{6} e^{0})

Simplify

sin (\frac{5 π}{6} e^{0}) : \frac{1}{2}

= \frac{1}{2}

\int (x + 1) [ln (x + 1) + c] d x

y^{2} y^{^{'}} = y^{2}

f (x) = x^{2} - 2 x

\int \frac{x ^{3}}{x ^{2} + 9} d x

\frac{d}{d x} (\frac{- 2 x ^{2} - 2}{( x - 1 ) ^{2} ( x + 1 ) ^{2}})

What is the limit as x approaches 0+of sin((5pi)/6 e^{sqrt(x)}) ?
The limit as x approaches 0+of sin((5pi)/6 e^{sqrt(x)}) is 1/2