What is the first derivative of 3x-5 ?

The first derivative of 3x-5 is 3

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derivative of 3x-5

derivative of

3 x - 5

3

Solution steps

\frac{d}{d x} (3 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (5)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 3 - 0

Simplify

= 3

\frac{d}{d x} ([x + (x + sin^{2} (x))^{5}]^{4})

y^{^{''}} - 4 y^{^{'}} + 20 y = 0

f (x) = (x - 1) (x + 1)^{3}

\frac{d}{d x} (2 x tanh (x))

- \frac{9}{( 6 t + 8 ) ^{\frac{3}{2}}}