What is the solution for y^'+y/t =e^{t^2} ?

The solution for y^'+y/t =e^{t^2} is y=(e^{t^2}}{2t}+\frac{c_{1})/t

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y^'+y/t =e^{t^2}

y^{^{'}} + \frac{y}{t} = e^{t^{2}}

y = \frac{e ^{t^{2}}}{2 t} + \frac{c _{1}}{t}

Solution steps

y^{'} (t) + \frac{y}{t} = e^{t^{2}}

Solve linear ODE:

y = \frac{e ^{t^{2}}}{2 t} + \frac{c _{1}}{t}

y = \frac{e ^{t^{2}}}{2 t} + \frac{c _{1}}{t}

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + y = \frac{e ^{x}}{1 + x ^{2}}

n \to \infty lim ({(1 + \frac{2}{n})^{4 n}})

y = x^{2} e^{x} - 2 x e^{x} + 9 e^{x}

\frac{d y}{d x} - 2 y = - 1

y^{^{'}} = 0.2 x

What is the solution for y^'+y/t =e^{t^2} ?
The solution for y^'+y/t =e^{t^2} is y=(e^{t^2}}{2t}+\frac{c_{1})/t