What is the derivative of (x-2^2*(x+4)) ?

The derivative of (x-2^2*(x+4)) is 3x^2-12

What is the first derivative of (x-2^2*(x+4)) ?

The first derivative of (x-2^2*(x+4)) is 3x^2-12

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\frac{d}{d x} ((x - 2)^{2} \cdot (x + 4))

3 x^{2} - 12

Solution steps

\frac{d}{d x} ((x - 2)^{2} (x + 4))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (x - 2)^{2}, g = x + 4

= \frac{d}{d x} ((x - 2)^{2}) (x + 4) + \frac{d}{d x} (x + 4) (x - 2)^{2}

\frac{d}{d x} ((x - 2)^{2}) = 2 (x - 2)

\frac{d}{d x} (x + 4) = 1

= 2 (x - 2) (x + 4) + 1 \cdot (x - 2)^{2}

Simplify

2 (x - 2) (x + 4) + 1 \cdot (x - 2)^{2} : 3 x^{2} - 12

= 3 x^{2} - 12

\frac{d}{d x} (\frac{2 cos ( x )}{x + 1})

x \to 0 + lim (x)

y^{^{'}} + y = e^{x} sin (e^{x})

y^{^{'}} - (y - 1)^{2} = 0

\int X d X

What is the derivative of (x-2^2*(x+4)) ?
The derivative of (x-2^2*(x+4)) is 3x^2-12
What is the first derivative of (x-2^2*(x+4)) ?
The first derivative of (x-2^2*(x+4)) is 3x^2-12