What is (\partial)/(\partial y)(x^2+xy) ?

The answer to (\partial)/(\partial y)(x^2+xy) is x

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(\partial)/(\partial y)(x^2+xy)

\frac{\partial}{\partial y} (x^{2} + x y)

x

Solution steps

\frac{\partial}{\partial y} (x^{2} + x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (x y) = x

= 0 + x

Simplify

= x

\frac{d}{d x} (\frac{9 x}{x})

\int \frac{2 - x}{x} d x

\frac{d}{d x} (cos^{2} (1 - x^{2}))

\frac{1 - 4 t}{3 + t}

\int \frac{( 2 z - 1 )}{2 z ^{2} - 6 z + 5} d z

What is (\partial)/(\partial y)(x^2+xy) ?
The answer to (\partial)/(\partial y)(x^2+xy) is x