What is the solution for x^2y^{''}-2xy^'+2y=x^2+2 ?

The solution for x^2y^{''}-2xy^'+2y=x^2+2 is y=c_{1}x^2+c_{2}x+x^2ln(x)-x^2+1

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x^2y^{''}-2xy^'+2y=x^2+2

x^{2} y^{^{''}} - 2 x y^{^{'}} + 2 y = x^{2} + 2

y = c_{1} x^{2} + c_{2} x + x^{2} ln (x) - x^{2} + 1

Solution steps

x^{2} y^{''} (x) - 2 x y^{'} (x) + 2 y = x^{2} + 2

Solve linear ODE:

y = c_{1} x^{2} + c_{2} x + x^{2} ln (x) - x^{2} + 1

y = c_{1} x^{2} + c_{2} x + x^{2} ln (x) - x^{2} + 1

\frac{d}{d x} (\frac{0.9 e ^{x}}{tan ( x )})

(x^{\frac{1}{3}})^{^{'}}

3 t^{3} - \frac{2}{t ^{2}}

f (x) = x^{2} - 6

\int_{0}^{\infty} 77 \frac{e ^{x}}{e ^{2 x} + 3} d x

What is the solution for x^2y^{''}-2xy^'+2y=x^2+2 ?
The solution for x^2y^{''}-2xy^'+2y=x^2+2 is y=c_{1}x^2+c_{2}x+x^2ln(x)-x^2+1