sum from n=0 to infinity of 2/(e^n)

Lösung

n = 0 \sum \infty \frac{2}{e ^{n}}

2 \cdot \frac{e}{e - 1}

Dezimale

3.16395 \dots

Schritte zur Lösung

n = 0 \sum \infty \frac{2}{e ^{n}}

Wende die Regel der konstanten Multiplikation:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 0 \sum \infty \frac{1}{e ^{n}}

Geometrischen Test der Reihe anwenden:

\frac{e}{e - 1}

= 2 \cdot \frac{e}{e - 1}

\frac{\partial}{\partial x} (sin (3 x - 4 y))

\frac{d}{d x} (cos (9))

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