What is the f(t)=sqrt((t^2+1)/(t^2-1)) ?

The f(t)=sqrt((t^2+1)/(t^2-1)) is

Popular >

f(t)=sqrt((t^2+1)/(t^2-1))

f (t) = \frac{t ^{2} + 1}{t ^{2} - 1}

Domain : t < - 1 or t > 1

Range : f (t) > 1

Intercepts : None

Asymptotes : Vertical t = - 1, t = 1, Horizontal y = 1

Extreme Points : None

Interval Notation

Domain : (- \infty, - 1) \cup (1, \infty)

Range : (1, \infty)

Solution steps

Domain of

\frac{t ^{2} + 1}{t ^{2} - 1} : t < - 1 or t > 1

Range of

\frac{t ^{2} + 1}{t ^{2} - 1} : f (t) > 1

Axis interception points of

\frac{t ^{2} + 1}{t ^{2} - 1} :

None

Asymptotes of

\frac{t ^{2} + 1}{t ^{2} - 1} :

Vertical

: t = - 1, t = 1,

Horizontal

: y = 1

Extreme Points of

\frac{t ^{2} + 1}{t ^{2} - 1} :

None

\int_{1}^{\infty} \frac{1}{5 x + 2} d x

\frac{d}{d x} (lo g_{7} (x^{2}))

\frac{d}{d x} (\frac{x ^{2} - y ^{2}}{x ^{2} + y ^{2}})

\frac{d}{d x} (6 (2 x - 9)^{5})

(5 x + y e^{(\frac{y}{x})}) d x - x e^{\frac{y}{x}} d y = 0