What is the derivative of arccos(1/2 x) ?

The derivative of arccos(1/2 x) is -1/(sqrt(4-x^2))

What is the first derivative of arccos(1/2 x) ?

The first derivative of arccos(1/2 x) is -1/(sqrt(4-x^2))

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\frac{d}{d x} (arccos (\frac{1}{2} x))

- \frac{1}{4 - x ^{2}}

Solution steps

\frac{d}{d x} (arccos (\frac{1}{2} x))

Simplify

arccos (\frac{1}{2} x) : arccos (\frac{x}{2})

= \frac{d}{d x} (arccos (\frac{x}{2}))

Apply the chain rule:

- \frac{1}{1 - ( \frac{x}{2} ) ^{2}} \frac{d}{d x} (\frac{x}{2})

= - \frac{1}{1 - ( \frac{x}{2} ) ^{2}} \frac{d}{d x} (\frac{x}{2})

\frac{d}{d x} (\frac{x}{2}) = \frac{1}{2}

= - \frac{1}{1 - ( \frac{x}{2} ) ^{2}} \cdot \frac{1}{2}

Simplify

- \frac{1}{1 - ( \frac{x}{2} ) ^{2}} \cdot \frac{1}{2} : - \frac{1}{4 - x ^{2}}

= - \frac{1}{4 - x ^{2}}

im pl i c i t e^{x y} + y^{3} = 2 arcsin (x) + ln (y)

\int (ln (x))^{5} \frac{1}{x} d x

\frac{d y}{d x} + x y = x

d er i v a t i v e f (x) = \frac{1}{4 x ^{2} + 3 x}

\int (2 x + 1) e^{- x} d x

What is the derivative of arccos(1/2 x) ?
The derivative of arccos(1/2 x) is -1/(sqrt(4-x^2))
What is the first derivative of arccos(1/2 x) ?
The first derivative of arccos(1/2 x) is -1/(sqrt(4-x^2))