What is (\partial)/(\partial y)(7e^xln(y)) ?

The answer to (\partial)/(\partial y)(7e^xln(y)) is (7e^x)/y

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(\partial)/(\partial y)(7e^xln(y))

\frac{\partial}{\partial y} (7 e^{x} ln (y))

\frac{7 e ^{x}}{y}

Solution steps

\frac{\partial}{\partial y} (7 e^{x} ln (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 e^{x} \frac{\partial}{\partial y} (ln (y))

Apply the common derivative:

\frac{\partial}{\partial y} (ln (y)) = \frac{1}{y}

= 7 e^{x} \frac{1}{y}

Simplify

7 e^{x} \frac{1}{y} : \frac{7 e ^{x}}{y}

= \frac{7 e ^{x}}{y}

x \to 6 lim (x (x - 3))

y^{^{''}} - 18 y^{^{'}} + 130 y = 0, y (0) = 0, y (\frac{π}{2}) = 1

\int \frac{3 x ^{2} + 3 x + 3}{x ^{2} + 1} d x

\frac{d}{d x} (x^{2} + \frac{4}{x} - 10)

\frac{d}{d x} (\frac{100}{x ^{5}})

What is (\partial)/(\partial y)(7e^xln(y)) ?
The answer to (\partial)/(\partial y)(7e^xln(y)) is (7e^x)/y