What is the sum from n=0 to infinity of 5/(n!) ?

The sum from n=0 to infinity of 5/(n!) is converges

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sum from n=0 to infinity of 5/(n!)

n = 0 \sum \infty \frac{5}{n !}

converges

Solution steps

n = 0 \sum \infty \frac{5}{n !}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 0 \sum \infty \frac{1}{n !}

Apply Series Ratio Test:

converges

= 5 converges

= converges

\frac{d}{d x} (\frac{1}{x ^{2} + 9})

(3, - 6), (5, - 5)

y = x^{3} - 1, y = x - 1

n = 0 \sum \infty \frac{3 ^{n}}{5 ^{2 n + 1}}

x \to 1 lim (x + 3 e x - 1 + 1)

What is the sum from n=0 to infinity of 5/(n!) ?
The sum from n=0 to infinity of 5/(n!) is converges