What is laplacetransform t-5 ?

The answer to laplacetransform t-5 is 1/(s^2)-5/s

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laplacetransform t-5

laplace transform

t - 5

\frac{1}{s ^{2}} - \frac{5}{s}

Solution steps

L {t - 5}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} - L {5}

L {t} : \frac{1}{s ^{2}}

L {5} : \frac{5}{s}

= \frac{1}{s ^{2}} - \frac{5}{s}

f (x) = \frac{8}{x ^{2}}, at x = 2

x \to 0 lim (\frac{2}{x + 5})

x^{2} + y^{2} = c^{2}

x \to - 2 lim (\frac{x ^{2} + 5 x + 6}{x})

\int \frac{2 x + 18}{x ^{2} + 10 x + 24} d x

What is laplacetransform t-5 ?
The answer to laplacetransform t-5 is 1/(s^2)-5/s