What is the derivative of ln(3x^2-5) ?

The derivative of ln(3x^2-5) is (6x)/(3x^2-5)

What is the first derivative of ln(3x^2-5) ?

The first derivative of ln(3x^2-5) is (6x)/(3x^2-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (ln (3 x^{2} - 5))

\frac{6 x}{3 x ^{2} - 5}

Solution steps

\frac{d}{d x} (ln (3 x^{2} - 5))

Apply the chain rule:

\frac{1}{3 x ^{2} - 5} \frac{d}{d x} (3 x^{2} - 5)

= \frac{1}{3 x ^{2} - 5} \frac{d}{d x} (3 x^{2} - 5)

\frac{d}{d x} (3 x^{2} - 5) = 6 x

= \frac{1}{3 x ^{2} - 5} \cdot 6 x

Simplify

\frac{1}{3 x ^{2} - 5} \cdot 6 x : \frac{6 x}{3 x ^{2} - 5}

= \frac{6 x}{3 x ^{2} - 5}

\frac{d}{d x} (\frac{1}{x})

\int x (x + 2) d x

\int_{0}^{1} 6^{3 x} d x

\int \frac{x ^{2} - 49}{x ^{3}} d x

\frac{\partial}{\partial x} (4 x y e^{x})

What is the derivative of ln(3x^2-5) ?
The derivative of ln(3x^2-5) is (6x)/(3x^2-5)
What is the first derivative of ln(3x^2-5) ?
The first derivative of ln(3x^2-5) is (6x)/(3x^2-5)