What is the integral from 7 to 9 of (x^2+2x-8) ?

The integral from 7 to 9 of (x^2+2x-8) is 434/3

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integral from 7 to 9 of (x^2+2x-8)

\int_{7}^{9} (x^{2} + 2 x - 8) d x

\frac{434}{3}

Decimal Notation

144.66666 \dots

Solution steps

\int_{7}^{9} x^{2} + 2 x - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{7}^{9} x^{2} d x + \int_{7}^{9} 2 x d x - \int_{7}^{9} 8 d x

\int_{7}^{9} x^{2} d x = \frac{386}{3}

\int_{7}^{9} 2 x d x = 32

\int_{7}^{9} 8 d x = 16

= \frac{386}{3} + 32 - 16

Simplify

\frac{386}{3} + 32 - 16 : \frac{434}{3}

= \frac{434}{3}

\frac{\partial}{\partial x} (sin (8 θ))

\int_{1}^{\infty} e^{- 9 x} d x

\int csc^{2} (y) d y

\frac{\partial}{\partial x} (5 x^{\frac{y}{z}})

x y^{^{'}} = y + 7 x^{2} sin (x), y (π) = 0

What is the integral from 7 to 9 of (x^2+2x-8) ?
The integral from 7 to 9 of (x^2+2x-8) is 434/3