What is the tangent of y=(4x)/(1+x^2),(4, 16/17) ?

The tangent of y=(4x)/(1+x^2),(4, 16/17) is y=-60/289 x+512/289

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tangent of y=(4x)/(1+x^2),(4, 16/17)

tangent of

y = \frac{4 x}{1 + x ^{2}}, (4, \frac{16}{17})

y = - \frac{60}{289} x + \frac{512}{289}

Solution steps

Find the slope of

y = \frac{4 x}{1 + x ^{2}} : \frac{d y}{d x} = \frac{4 ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}}

Compute the slope of

y = \frac{4 x}{1 + x ^{2}}

(4, \frac{16}{17}) : m = - \frac{60}{289}

Find the line with slope m=

- \frac{60}{289}

and passing through

(4, \frac{16}{17}) : y = - \frac{60}{289} x + \frac{512}{289}

y = - \frac{60}{289} x + \frac{512}{289}

\int_{0}^{\frac{π}{2}} - 3 sin^{2} (3 x) d x

\frac{( 3 - 2 s )}{( s ^{2} + 4 s + 5 )}

\int x^{2} - 7 x + 5 d x

\int_{\frac{9}{8}}^{4} \frac{1}{1 - x ^{2}} d x

\int - \frac{x}{1 + x ^{2}} d x

What is the tangent of y=(4x)/(1+x^2),(4, 16/17) ?
The tangent of y=(4x)/(1+x^2),(4, 16/17) is y=-60/289 x+512/289