What is the solution for (x^2-xy)(dy)/(dx)+y^2=0 ?

The solution for (x^2-xy)(dy)/(dx)+y^2=0 is y=-\W(-(c_{1})/x)x

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(x^2-xy)(dy)/(dx)+y^2=0

(x^{2} - x y) \frac{d y}{d x} + y^{2} = 0

y = - W (- \frac{c _{1}}{x}) x

Solution steps

(x^{2} - x y) \frac{d y}{d x} + y^{2} = 0

Solve using substitution:

y = - W (- \frac{c _{1}}{x}) x

y = - W (- \frac{c _{1}}{x}) x

y = t

\int \frac{2 x - 1}{x ^{2}} d x

3 x^{3} - x^{2} + 9 x - 9

\frac{s - 2}{s ^{2} - s - 6}

\frac{d}{d x} (\frac{arcsin ( 3 x )}{x})

What is the solution for (x^2-xy)(dy)/(dx)+y^2=0 ?
The solution for (x^2-xy)(dy)/(dx)+y^2=0 is y=-\W(-(c_{1})/x)x