What is the derivative of-sin(4x) ?

The derivative of-sin(4x) is -cos(4x)*4

What is the first derivative of-sin(4x) ?

The first derivative of-sin(4x) is -cos(4x)*4

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\frac{d}{d x} (- sin (4 x))

- cos (4 x) \cdot 4

Solution steps

\frac{d}{d x} (- sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{d}{d x} (4 x)

= cos (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= - cos (4 x) \cdot 4

y = e^{x^{4}}

\frac{d y}{d x} = (1 + e^{2 x})

\frac{d}{d x} (\frac{x ^{2}}{x - 9})

(- 8, 9), (- 2, - 3)

x y + y^{^{'}} = 100 x

What is the derivative of-sin(4x) ?
The derivative of-sin(4x) is -cos(4x)*4
What is the first derivative of-sin(4x) ?
The first derivative of-sin(4x) is -cos(4x)*4