What is (\partial)/(\partial x)(3y^2-x^2) ?

The answer to (\partial)/(\partial x)(3y^2-x^2) is -2x

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(\partial)/(\partial x)(3y^2-x^2)

\frac{\partial}{\partial x} (3 y^{2} - x^{2})

- 2 x

Solution steps

\frac{\partial}{\partial x} (3 y^{2} - x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 y^{2}) - \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (3 y^{2}) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 0 - 2 x

Simplify

= - 2 x

\frac{d}{d x} (\frac{x ^{2} + 4}{4 x ^{3} - 5 x})

- 5 e^{- 5 x + 2}

\int \frac{e ^{x}}{e ^{x} + e} d x

\int \frac{1}{y} d y

\frac{1}{2 x + 1}

What is (\partial)/(\partial x)(3y^2-x^2) ?
The answer to (\partial)/(\partial x)(3y^2-x^2) is -2x