What is the derivative of f(x)=17e^e-ex^e ?

The derivative of f(x)=17e^e-ex^e is -e^2x^{e-1}

What is the first derivative of f(x)=17e^e-ex^e ?

The first derivative of f(x)=17e^e-ex^e is -e^2x^{e-1}

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derivative of

f (x) = 17 e^{e} - e x^{e}

- e^{2} x^{e - 1}

Solution steps

\frac{d}{d x} (17 e^{e} - e x^{e})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (17 e^{e}) - \frac{d}{d x} (e x^{e})

\frac{d}{d x} (17 e^{e}) = 0

\frac{d}{d x} (e x^{e}) = e^{2} x^{e - 1}

= 0 - e^{2} x^{e - 1}

Simplify

= - e^{2} x^{e - 1}

e^{- t} t sin (2 t)

\frac{d}{d t} (2 t^{- \frac{3}{4}})

x \to \infty lim ((e)^{x})

\frac{\partial}{\partial x} (x^{2} (\frac{y}{x}))

(f (x) (x)^{g (x)})^{'}

What is the derivative of f(x)=17e^e-ex^e ?
The derivative of f(x)=17e^e-ex^e is -e^2x^{e-1}
What is the first derivative of f(x)=17e^e-ex^e ?
The first derivative of f(x)=17e^e-ex^e is -e^2x^{e-1}