y^'=(x+y+1)^2

解答

y^{^{'}} = (x + y + 1)^{2}

y = tan (x + c_{1}) - x - 1

求解步骤

y^{'} (x) = (x + y + 1)^{2}

使用替代法求解:

y = tan (x + c_{1}) - x - 1

y = tan (x + c_{1}) - x - 1

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