What is the derivative of xln(x-x) ?

The derivative of xln(x-x) is ln(x)

What is the first derivative of xln(x-x) ?

The first derivative of xln(x-x) is ln(x)

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\frac{d}{d x} (x ln (x) - x)

ln (x)

Solution steps

\frac{d}{d x} (x ln (x) - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x ln (x)) - \frac{d x}{d x}

\frac{d}{d x} (x ln (x)) = ln (x) + 1

\frac{d x}{d x} = 1

= ln (x) + 1 - 1

Simplify

= ln (x)

\frac{\partial}{\partial y} (x cos (y - x))

\int \frac{3 x ^{2}}{x ^{3} + 7} d x

\frac{d}{d x} (x y)

y^{^{''}} + 2 y^{^{'}} + 2 y = e^{- t} sin (t)

f^{^{'}} (x) = (\frac{1 - sec ( x )}{tan ( x )})

What is the derivative of xln(x-x) ?
The derivative of xln(x-x) is ln(x)
What is the first derivative of xln(x-x) ?
The first derivative of xln(x-x) is ln(x)