en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

area y=2x^3,x=0,x=2

Solution

area

y = 2 x^{3}, x = 0, x = 2

Solution

8

Solution steps

Apply the area formula:

\int_{0}^{2} 2 x^{3} d x

Solve

\int_{0}^{2} 2 x^{3} d x : 8

The area is:

= 8

Graph

Popular Examples

derivative of ln|ln(3x|)

\frac{d}{d x} (ln ∣ ln (3 x) ∣)

derivative of e^{2x-4}

\frac{d}{d x} (e^{2 x - 4})

derivative of f(x)=(2x)/(x^2+4)

d er i v a t i v e f (x) = \frac{2 x}{x ^{2} + 4}

integral of-9x^2sec(3x^3+1)tan(3x^3+1)

\int - 9 x^{2} sec (3 x^{3} + 1) tan (3 x^{3} + 1) d x

integral of inx

\int in x d x

Frequently Asked Questions (FAQ)

What is area y=2x^3,x=0,x=2 ?
The answer to area y=2x^3,x=0,x=2 is 8