derivative of x^4+2x^2-x

Lösung

\frac{d}{d x} (x^{4} + 2 x^{2} - x)

4 x^{3} + 4 x - 1

Schritte zur Lösung

\frac{d}{d x} (x^{4} + 2 x^{2} - x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

= 4 x^{3} + 4 x - 1

\frac{\partial}{\partial x} (1 x)

(1 + y) \frac{d y}{d t} = 6 t, y (2) = 5

\int \frac{x ^{2} - 2}{x + 3} d x

\int \frac{( x + 1 )}{x ^{2} + 2 x} d x

t an g e n t f (x) = x^{2} + 5 x - 2, at x = - 1