What is the derivative of f(x)=x^2+x-2 ?

The derivative of f(x)=x^2+x-2 is 2x+1

What is the first derivative of f(x)=x^2+x-2 ?

The first derivative of f(x)=x^2+x-2 is 2x+1

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derivative of

f (x) = x^{2} + x - 2

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 2 x + 1 - 0

Simplify

= 2 x + 1

\frac{d}{d x} (\frac{cos ( x )}{ln ( x )})

\int cos (x) a^{s i n (x)} d x

\frac{\partial}{\partial x} (\frac{x}{yz})

\int (\frac{1}{1 + e ^{x}}) d x

x \to \infty lim (- e^{- a x})

What is the derivative of f(x)=x^2+x-2 ?
The derivative of f(x)=x^2+x-2 is 2x+1
What is the first derivative of f(x)=x^2+x-2 ?
The first derivative of f(x)=x^2+x-2 is 2x+1