What is the derivative of arcsin(6x)+arccos(6x) ?

The derivative of arcsin(6x)+arccos(6x) is 0

What is the first derivative of arcsin(6x)+arccos(6x) ?

The first derivative of arcsin(6x)+arccos(6x) is 0

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derivative of

arcsin (6 x) + arccos (6 x)

0

Solution steps

\frac{d}{d x} (arcsin (6 x) + arccos (6 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arcsin (6 x)) + \frac{d}{d x} (arccos (6 x))

\frac{d}{d x} (arcsin (6 x)) = \frac{6}{1 - 36 x ^{2}}

\frac{d}{d x} (arccos (6 x)) = - \frac{6}{1 - 36 x ^{2}}

= \frac{6}{1 - 36 x ^{2}} - \frac{6}{1 - 36 x ^{2}}

Simplify

= 0

\frac{d}{d x} (x^{4} - 4 x^{2} + 3)

\frac{23}{( 8 x - 1 ) ^{2}}

x^{7}

\int \frac{cos ( 3 x )}{sin ^{2} ( 3 x )} d x

What is the derivative of arcsin(6x)+arccos(6x) ?
The derivative of arcsin(6x)+arccos(6x) is 0
What is the first derivative of arcsin(6x)+arccos(6x) ?
The first derivative of arcsin(6x)+arccos(6x) is 0