What is (\partial)/(\partial x)(x^2y^{1/3}) ?

The answer to (\partial)/(\partial x)(x^2y^{1/3}) is 2xy^{1/3}

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(\partial)/(\partial x)(x^2y^{1/3})

\frac{\partial}{\partial x} (x^{2} y^{\frac{1}{3}})

2 x y^{\frac{1}{3}}

Solution steps

\frac{\partial}{\partial x} (x^{2} y^{\frac{1}{3}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{\frac{1}{3}} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{\frac{1}{3}} \cdot 2 x^{2 - 1}

Simplify

= 2 x y^{\frac{1}{3}}

\frac{d}{d t} (e^{- t} - e^{- t} t)

f (x) = e^{x c o s (x)}

\frac{x}{x ^{2} - 8}

\int x - (\frac{1}{2})^{x} d x

x \to \infty lim (4^{x} - 1)

What is (\partial)/(\partial x)(x^2y^{1/3}) ?
The answer to (\partial)/(\partial x)(x^2y^{1/3}) is 2xy^{1/3}