What is the limit as x approaches 0 of 1/(2x^2+x) ?

The limit as x approaches 0 of 1/(2x^2+x) is diverges

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limit as x approaches 0 of 1/(2x^2+x)

x \to 0 lim (\frac{1}{2 x ^{2} + x})

diverges

Solution steps

x \to 0 lim (\frac{1}{2 x ^{2} + x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{2 x ^{2} + x}) = \infty

x \to 0 - lim (\frac{1}{2 x ^{2} + x}) = - \infty

= diverges

\int \frac{9}{4 + 9 x} d x

\int \frac{y}{a ^{2} - y ^{2}} d y

x \to 0 lim (x^{2} csc (x))

\frac{\partial}{\partial y} (3 x + 4 y)

What is the limit as x approaches 0 of 1/(2x^2+x) ?
The limit as x approaches 0 of 1/(2x^2+x) is diverges