What is the solution for 1/4 ((dy)/(dt))+10y=5 ?

The solution for 1/4 ((dy)/(dt))+10y=5 is y=-(e^{-40t-c_{1}})/2+1/2

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1/4 ((dy)/(dt))+10y=5

\frac{1}{4} (\frac{d y}{d t}) + 10 y = 5

y = - \frac{e ^{- 40 t - c_{1}}}{2} + \frac{1}{2}

Solution steps

\frac{1}{4} (\frac{d y}{d t}) + 10 y = 5

Solve separable ODE:

y = - \frac{e ^{- 40 t - c_{1}}}{2} + \frac{1}{2}

y = - \frac{e ^{- 40 t - c_{1}}}{2} + \frac{1}{2}

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n = 2 \sum \infty \frac{( - 1 ) ^{n}}{n ln ( n )}

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What is the solution for 1/4 ((dy)/(dt))+10y=5 ?
The solution for 1/4 ((dy)/(dt))+10y=5 is y=-(e^{-40t-c_{1}})/2+1/2