What is the solution for sqrt(1-y^2)dx=sqrt(1-x^2)dy ?

The solution for sqrt(1-y^2)dx=sqrt(1-x^2)dy is y=sin(arcsin(x)+c_{1})

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sqrt(1-y^2)dx=sqrt(1-x^2)dy

1 - y^{2} d x = 1 - x^{2} d y

y = sin (arcsin (x) + c_{1})

Solution steps

1 - y^{2} d x = 1 - x^{2} d y

Solve separable ODE:

y = sin (arcsin (x) + c_{1})

y = sin (arcsin (x) + c_{1})

\int_{0}^{2} \frac{2 x}{( x ^{2} + 5 ) ^{3}} d x

x \to 0 lim (\frac{- 2 e ^{- x}}{2 x - 2})

\int \frac{e ^{4 x}}{- 4 x} d x

x \to + 0 lim (\frac{( 3 e ^{x} - 3 )}{x})

\int_{0}^{1} 0.5 e^{- 2 x} d x

What is the solution for sqrt(1-y^2)dx=sqrt(1-x^2)dy ?
The solution for sqrt(1-y^2)dx=sqrt(1-x^2)dy is y=sin(arcsin(x)+c_{1})