(\partial)/(\partial x)(ln(x-2y)-z)

解

\frac{\partial}{\partial x} (ln (x - 2 y) - z)

\frac{1}{x - 2 y}

解答ステップ

\frac{\partial}{\partial x} (ln (x - 2 y) - z)

y, z

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (ln (x - 2 y)) - \frac{\partial}{\partial x} (z)

\frac{\partial}{\partial x} (ln (x - 2 y)) = \frac{1}{x - 2 y}

\frac{\partial}{\partial x} (z) = 0

= \frac{1}{x - 2 y} - 0

簡素化

= \frac{1}{x - 2 y}