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Popular >

y^'+y=-1

Solution

y^{^{'}} + y = - 1

Solution

y = e^{- t - c_{1}} - 1

Solution steps

y^{'} (t) + y = - 1

Solve separable ODE:

y = e^{- t - c_{1}} - 1

y = e^{- t - c_{1}} - 1

Popular Examples

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\frac{d}{d x} (tan (arccos (x)))

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\int_{0}^{1} (x + 1)^{3} d x

limit as x approaches-1 of 2-3x

x \to - 1 lim (2 - 3 x)

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x \to \infty lim (8 - 2 x)

(\partial)/(\partial y)(x^2+y^2-1)

\frac{\partial}{\partial y} (x^{2} + y^{2} - 1)

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=-1 ?
The solution for y^'+y=-1 is y=e^{-t-c_{1}}-1