derivative f(x)=sqrt(2x+2)

Lösung

ableitung von

f (x) = 2 x + 2

\frac{1}{2 x + 2}

Schritte zur Lösung

\frac{d}{d x} (2 x + 2)

Wende die Kettenregel an:

\frac{1}{2 2 x + 2} \frac{d}{d x} (2 x + 2)

= \frac{1}{2 2 x + 2} \frac{d}{d x} (2 x + 2)

\frac{d}{d x} (2 x + 2) = 2

= \frac{1}{2 2 x + 2} \cdot 2

Vereinfache

\frac{1}{2 2 x + 2} \cdot 2 : \frac{1}{2 x + 2}

= \frac{1}{2 x + 2}

x \to 4 lim (\frac{7}{x - 4})

x \to 0 lim (3 x^{2} + 5)

\int \frac{1}{x ^{2} + x + 1} d x

\int \frac{9 + x + x ^{2}}{x} d x

d er i v a t i v e (x^{2} + 3) (x^{3} + 5)