What is the derivative of 2e^{3t} ?

The derivative of 2e^{3t} is 6e^{3t}

What is the first derivative of 2e^{3t} ?

The first derivative of 2e^{3t} is 6e^{3t}

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derivative of

2 e^{3 t}

6 e^{3 t}

Solution steps

\frac{d}{d t} (2 e^{3 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (e^{3 t})

Apply the chain rule:

e^{3 t} \frac{d}{d t} (3 t)

= e^{3 t} \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= 2 e^{3 t} \cdot 3

Simplify

= 6 e^{3 t}

3600 (1 - \frac{t}{60})^{2}

x \to 3 lim (\frac{∣ x + 3 ∣}{x + 3})

\frac{d}{d x} (\frac{4}{x ^{4}} + \frac{1}{x} + 2)

x \to 0 lim ((1 + sin (3 x))^{\frac{1}{x}})

\frac{d}{d x} (\frac{π x ^{2}}{2})

What is the derivative of 2e^{3t} ?
The derivative of 2e^{3t} is 6e^{3t}
What is the first derivative of 2e^{3t} ?
The first derivative of 2e^{3t} is 6e^{3t}