What is (\partial)/(\partial x)(4*e^x-2*x*e^y) ?

The answer to (\partial)/(\partial x)(4*e^x-2*x*e^y) is 4e^x-2e^y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4e^x-2x*e^y)

\frac{\partial}{\partial x} (4 \cdot e^{x} - 2 \cdot x \cdot e^{y})

4 e^{x} - 2 e^{y}

Solution steps

\frac{\partial}{\partial x} (4 e^{x} - 2 x e^{y})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 e^{x}) - \frac{\partial}{\partial x} (2 x e^{y})

\frac{\partial}{\partial x} (4 e^{x}) = 4 e^{x}

\frac{\partial}{\partial x} (2 x e^{y}) = 2 e^{y}

= 4 e^{x} - 2 e^{y}

\frac{d}{d x} ((4 x - 1)^{\frac{1}{3}})

\frac{x ^{4} + 6 x - 1}{7 x ^{2} - 6 x + 1}

sin (15 x)

\int 6 - x^{2} d x

y^{^{'}} = \frac{1 - y ^{2}}{t}

What is (\partial)/(\partial x)(4*e^x-2*x*e^y) ?
The answer to (\partial)/(\partial x)(4*e^x-2*x*e^y) is 4e^x-2e^y