What is the derivative of y=x^2ln(7x) ?

The derivative of y=x^2ln(7x) is 2xln(7x)+x

What is the first derivative of y=x^2ln(7x) ?

The first derivative of y=x^2ln(7x) is 2xln(7x)+x

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derivative of

y = x^{2} ln (7 x)

2 x ln (7 x) + x

Solution steps

\frac{d}{d x} (x^{2} ln (7 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = ln (7 x)

= \frac{d}{d x} (x^{2}) ln (7 x) + \frac{d}{d x} (ln (7 x)) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (ln (7 x)) = \frac{1}{x}

= 2 x ln (7 x) + \frac{1}{x} x^{2}

\frac{1}{x} x^{2} = x

= 2 x ln (7 x) + x

a \to \infty lim (a^{2})

\int t^{2} e^{4 t} d t

\int 9 x e^{6 x} d x

\frac{d y}{d x} = 4 + e^{y - 4 x + 5}

\frac{d}{d x} (e^{5 - 2 x})

What is the derivative of y=x^2ln(7x) ?
The derivative of y=x^2ln(7x) is 2xln(7x)+x
What is the first derivative of y=x^2ln(7x) ?
The first derivative of y=x^2ln(7x) is 2xln(7x)+x