What is the integral of cos(r^2) ?

The integral of cos(r^2) is sqrt(pi/2)\C(sqrt(2/pi)r)+C

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integral of cos(r^2)

\int cos (r^{2}) d r

\frac{π}{2} C (\frac{2}{π} r) + C

Solution steps

\int cos (r^{2}) d r

Use the nonelementary integral:

\int cos (x^{2}) d x = \frac{π}{2} C (\frac{2}{π} x)

= \frac{π}{2} C (\frac{2}{π} r)

Add a constant to the solution

= \frac{π}{2} C (\frac{2}{π} r) + C

x y^{^{'}} = (1 - x) y + x^{2} + x^{3}

y^{^{''}} + 4 y^{^{'}} = cos^{2} (x)

\int - \frac{1}{10 - x} d x

\int cos^{3} (x) (sin (x)) d x

y = x^{2} - 8, y = 1

What is the integral of cos(r^2) ?
The integral of cos(r^2) is sqrt(pi/2)\C(sqrt(2/pi)r)+C