What is the derivative of ln(cos(x)+x) ?

The derivative of ln(cos(x)+x) is -tan(x)+1

What is the first derivative of ln(cos(x)+x) ?

The first derivative of ln(cos(x)+x) is -tan(x)+1

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\frac{d}{d x} (ln (cos (x)) + x)

- tan (x) + 1

Solution steps

\frac{d}{d x} (ln (cos (x)) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (cos (x))) + \frac{d x}{d x}

\frac{d}{d x} (ln (cos (x))) = - tan (x)

\frac{d x}{d x} = 1

= - tan (x) + 1

\int \frac{x ^{2}}{( 9 x ^{2} - 4 ) ^{\frac{5}{2}}} d x

\int_{0}^{π} (5 e^{x} + 3 sin (x)) d x

\frac{\partial}{\partial x} (3 t sin^{2} (t))

f (x) = 5 x - 1

x^{4} y^{^{'}} + 3 x^{3} y = x^{2} e^{x}

What is the derivative of ln(cos(x)+x) ?
The derivative of ln(cos(x)+x) is -tan(x)+1
What is the first derivative of ln(cos(x)+x) ?
The first derivative of ln(cos(x)+x) is -tan(x)+1