What is the integral from-1 to 1 of pi(1-x^2) ?

The integral from-1 to 1 of pi(1-x^2) is pi 4/3

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integral from-1 to 1 of pi(1-x^2)

\int_{- 1}^{1} π (1 - x^{2}) d x

π \frac{4}{3}

Decimal Notation

4.18879 \dots

Solution steps

\int_{- 1}^{1} π (1 - x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{- 1}^{1} 1 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{- 1}^{1} 1 d x - \int_{- 1}^{1} x^{2} d x)

\int_{- 1}^{1} 1 d x = 2

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

= π (2 - \frac{2}{3})

Join

2 - \frac{2}{3} : \frac{4}{3}

= π \frac{4}{3}

x \to \infty lim (1.003)

y^{^{'}} = x y^{3} (1 + x^{2})^{- \frac{1}{2}}

f (x) = (x^{2} + 8) (7 - x)

x \to 1 lim (e^{\frac{1}{x - 1}})

\int \frac{4 x}{3 x} d x

What is the integral from-1 to 1 of pi(1-x^2) ?
The integral from-1 to 1 of pi(1-x^2) is pi 4/3